**Hi,**

I'm having trouble actually understanding this question and my lecture is responding to emails or calls.[/b]

I'm having trouble actually understanding this question and my lecture is responding to emails or calls.

SPSS can also be used to find critical values. Use transform/compute and then mark the

“function group” “inverse df” so that you can find available distributions in the “Functions

and Special Variables” box and by moving this into the “numeric expression” box where

you have to specify distribution parameters and the corresponding probability. Generate

critical values on the 95% level from the following distributions and present them in your

report:

i. Standard normal.

ii. T distribution with 20 df and 450 df.

iii. Chi square distribution with 5 df and 50 df.

iv. Uniform distribution with a=3, b=10.

v. F distribution with (4,20).

For the last part of this exercise we need the following function: Use transform/compute

and then mark the “function group” “CDF & Noncentral CDF” so that you can find

available cumulative distribution functions in the “Functions and Special Variables” box.

Make use of Cdf.Normal to solve vi.

vi. Find the probability P(−1.96 < x < 1.96), where x is standard normally

distributed.

**What exactly am i suppose to show???**

The distribution on a histogram???

I created the variable at the 95% level giving me 1.64 using the below code

TRANSFORM/COMPUTE/”FUNCTION”Inversse df/idf normal

NORMAL (0.95,0,1)

The distribution on a histogram???

I created the variable at the 95% level giving me 1.64 using the below code

TRANSFORM/COMPUTE/”FUNCTION”Inversse df/idf normal

NORMAL (0.95,0,1)

But what now???

Thanks in advance for any help I can get